Ariana Grande, Tame Impala and Childish Gambino will headline Coachella 2019.
The ‘Imagine’ singer, Kevin Parker-fronted indie band and acclaimed rapper – whose real name is Donald Glover – are all set to perform twice at the annual music extravaganza, which is held between April 12 and April 14 and April 19 and April 21 in Indio, California.
Ariana is set to perform on both Sundays, Kevin and co on both Saturdays and Gambino will appear on both Fridays.
Sharing her excitement for the headline slot on Twitter, Ariana, 25, wrote: "Humbled and excited as hell Coachella. Thank u. (sic)"
The ‘thank u, next’ hitmaker is no stranger to the festival.
Last year, the superstar made a surprise appearance during Kygo’s set to perform what was then her new single ‘No Tears Left To Cry’ for her debut at the world famous event.
BLACKPINK will become the first all-female K-Pop group to play the Coachella Valley Music And Arts Festival.
Also on the bill this year are The 1975, Janelle Monae, Solange and Weezer.
It was recently reported that Kanye West was set to perform, but the ‘All Day’ rapper allegedly pulled out because the staging was "artistically limiting".
An insider told TMZ: "These 40×60 stages are so archaic. It’s the same type of stage on which Shakespeare’s works were performed hundreds of years ago."
2018 saw Beyonce, Eminem and The Weeknd headline.
The ‘Halo’ hitmaker reunited with her Destiny’s Child bandmates Michelle Williams and Kelly Rowland to perform a show-stopping surprise medley during the singer’s headline slot – comprised of ‘Lose My Breath’, ‘Say My Name’ and ‘Soldier’ – for their first live performance together in three years.
Tickets for Coachella go on sale on Friday (04.01.19).
Ariana Grande to headline Coachella 2019
